Distance from San Francisco del Rincón to Tepatitlán de Morelos
How far is it from San Francisco del Rincón to Tepatitlán de Morelos? About 60 mi in a straight line and 78 mi by road. Driving time, flight time, midpoint and route details.
San Francisco del Rincón and Tepatitlán de Morelos are about 60 mi (97 km) apart in a straight line. By road that works out to roughly 78 mi (126 km), a drive of about 1 hr 48 min. A nonstop flight covers the great-circle distance in approximately 37 min.
| Straight-line distance | 60 mi / 97 km |
| Road distance (est.) | 78 mi / 126 km |
| Driving time (est.) | 1 hr 48 min |
| Nonstop flight (est.) | 37 min |
| Driving fuel (est., 1-way) | $10 |
| Typical flight fare | $80–$250 |
| Geographic midpoint | 20.918, -102.310 |
How these estimates work
Straight-line distance uses the haversine formula on each city's coordinates. Road distance applies a circuity factor (~1.2–1.4×) and driving time a blended average speed. Flight time uses typical jet cruise speed plus ~30 minutes for taxi, climb and descent. Treat all figures as planning estimates.
Frequently asked questions
San Francisco del Rincón to Tepatitlán de Morelos is about 60 mi (97 km) in a straight line, and roughly 78 mi (126 km) by road.