Distance from São Sebastião do Paraíso to Sertãozinho
How far is it from São Sebastião do Paraíso to Sertãozinho? About 66 mi in a straight line and 86 mi by road. Driving time, flight time, midpoint and route details.
São Sebastião do Paraíso and Sertãozinho are about 66 mi (107 km) apart in a straight line. By road that works out to roughly 86 mi (139 km), a drive of about 1 hr 59 min. A nonstop flight covers the great-circle distance in approximately 37 min.
| Straight-line distance | 66 mi / 107 km |
| Road distance (est.) | 86 mi / 139 km |
| Driving time (est.) | 1 hr 59 min |
| Nonstop flight (est.) | 37 min |
| Driving fuel (est., 1-way) | $11 |
| Typical flight fare | $80–$250 |
| Geographic midpoint | -21.028, -47.490 |
How these estimates work
Straight-line distance uses the haversine formula on each city's coordinates. Road distance applies a circuity factor (~1.2–1.4×) and driving time a blended average speed. Flight time uses typical jet cruise speed plus ~30 minutes for taxi, climb and descent. Treat all figures as planning estimates.
Frequently asked questions
São Sebastião do Paraíso to Sertãozinho is about 66 mi (107 km) in a straight line, and roughly 86 mi (139 km) by road.